Question

find the remaining parts of the quadrantal spherical triangles (c=90°) given the following, giveb parts b= 45°20 a=76°40

Answer 1

Cos$90°=\frac{Cos\>C-Cos45°20'Cos76°40'}{Sin45°20'\>Sin76°40'}$

$C=80°40'$

$\frac{Sin\>A°}{Sin76°40'}=\frac{Sin90°}{Sin80°40'}$

$A=80°26'$

$\frac{SinB°}{Sin\>45°20'}=\frac{Sin\>90°}{Sin\>80°40'}$

$B=46°7'$