Question

A conveyor is used to lift paper to a shredder. The most efficient operating angle of elevation for the conveyor is 37.8°. The paper is to be elevated 16.0 m. What length (in m) of conveyor is needed? (Round your answer to three significant digits.)

Answer 1

Sin $37.8°=\frac{16}{L}$

$L=\frac{16}{Sin\>37.8°}$

$=27.1m$