Given that the cosine of an angle is cos (∅) = 1/2°, what height of the triangle formed by this? ( The terminal point for this angle is (1,y) solve for y ).
y=sin(θ)=1−cos2(θ)=1−14=32.y=\sin (\theta)=\sqrt{1-\cos^2(\theta)}=\sqrt{1-\frac{1}{4}}=\frac{\sqrt{3}}{2}.y=sin(θ)=1−cos2(θ)=1−41=23.
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