if P (2π/3) = ( -1/2 , /3/2) then cos Ø =?
P(2π/3)=(−1/2,/3/2)∴Ø=2π/3So,cosØ=cos(2π/3)=cos(π−π3)=−cos(π3)=−12P (2π/3) = ( -1/2 , /3/2) \\\thereforeØ = 2π/3 \\So, \cos Ø = \cos (2π/3) \\= \cos (π-\dfrac π3) \\=-\cos (\dfrac π3) \\=-\dfrac12P(2π/3)=(−1/2,/3/2)∴Ø=2π/3So,cosØ=cos(2π/3)=cos(π−3π)=−cos(3π)=−21
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