Explain the Pythagorean Theorem, its proofs and applications.
Pythagoras Theorem
The Pythagoras Theorem states that the sum of the squares of the base and perpendicular is equal to the square of the hypotenuse in a right-angled triangle. Pythagoras' theorem states that if a triangle is right-angled (90 degrees), the square of the hypotenuse equals the sum of the squares of the other two sides.
Given a right angled triangle below,
the Pythagoras Theorem formula is given as,
"(Hypotenuse)^2=(Base)^2+(Perpendicular)^2"
Pythagoras Theorem proof
The proof of the Pythagoras Theorem involves the concept of similarity of the triangle. It states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Given a right-angled triangle PQR, right angled at Q.
We proof that, "{PR^2}={PQ^2}+{QR^2}"
Draw a perpendicular line QD meeting PR at D.
We know that, "\\Delta RDQ\\sim\\Delta RQP"
So,
"{RD\\over QR}={QR\\over PR}" (Corresponding sides of similar triangles)
"\\implies{QR^2}=RD\\times PR.......(1)"
Also,
"\\Delta QDP\\sim\\Delta RQP"
So,
"{PD\\over PQ}={PR\\over PR}" (Corresponding sides of similar triangles)
So,
"PQ^2=PD\\times RP.......(2)"
Adding equation (1) and (2), we get,
"QR^2+PQ^2=(RD\\times PR)+(PD\\times PR)\\\\\n\\implies QR^2+PQ^2=PR(RD+PD)"
From the figure,
"RD+PD=PR"
Therefore,
"PR^2=PQ^2+QR^2" as required.
Applications of Pythagoras Theorem
Comments
Leave a comment