Question #281179

if the side of triangle are 16,20 and 27 respectivly,what is the lenght of the bisector of the largest angle?


1
Expert's answer
2021-12-20T16:38:04-0500






Using cosine rule;


272=162+2022×16×20cos2θ27^2=16^2+20^2-2×16×20\>cos \>2\theta


2θ=96.552\theta=96.55

θ=48.28\theta=48.28


202=272+1622×16×27Cosβ20^2=27^2+16^2-2×16×27\>Cos\>\beta


β=47.38\beta=47.38


16Sin84.34=xSin47.38\frac{16}{Sin\>84.34}=\frac{x}{Sin\>47.38}


x=11.83x=11.83



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