Answer to Question #281179 in Trigonometry for boboy

Question

if the side of triangle are 16,20 and 27 respectivly,what is the lenght of the bisector of the largest angle?

Answer 1

Using cosine rule;

$27^2=16^2+20^2-2×16×20\>cos \>2\theta$

$2\theta=96.55$

$\theta=48.28$

$20^2=27^2+16^2-2×16×27\>Cos\>\beta$

$\beta=47.38$

$\frac{16}{Sin\>84.34}=\frac{x}{Sin\>47.38}$

$x=11.83$