Question

1. Solve the spherical triangle ABC right angled C given c= 56°13´ and b=48°30´.

Answer 1

$S=\frac{1}{2}absinC$

$a+b+c=180^o$

$a=180-c-b$

$a=180-56^o13$^'$-48^o30$^'

$a=71^o32$^'