Answer to Question #2711 in Trigonometry for Abhyuday singh
Show that:-
(i) sin 18° = (√5-1)/4
(ii)Evaluate tan 11.¼°
1
2011-06-23T14:46:42-0400
& i)
sin 18°& = 0.309
(√5-1)/4& = 0.309
ii) tan 11.¼°& = tan 11.25°& = 0.20345
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