Answer to Question #263727 in Trigonometry for John

Question

Two points X and Y, 1000 m apart are located on a straight road running east and west. From

X, the bearing of a tower is 32°W of N and from Y the bearing of the town 26° N of E. Determine

the shortest distance of the tower from the road.

Answer 1

i....Cos32°=100/d

d=100/Cos32°

d=117.9m

ii.....Cos26°=100/d

d=100/Cos26°

d=111.3m

Therefore, the shortest distance = 111.3m