The bearing of a lighthouse from ship A is N29°E and the bearing of that lighthouse from ship B is N61°W. If ship A and ship B are on the east-west line 200 kilometers apart, how far is ship B from the lighthouse?
Let the distance be denoted by X which is the Adjacent side of the triangle.
Use the formula; SOH CAH TOA,SOH\ CAH\ TOA, \\SOH CAH TOA,
Cosθ=AdjecentHypotenuse ⟹ Cos 29∘ =Adjacent200 ⟹ 200 Cos 29∘=Adjacent∴ Adjacent=174.92kmCos\theta=\frac{Adjecent}{Hypotenuse} \implies Cos\ 29^{\circ}\ = \frac{Adjacent}{200}\\ \implies200\ Cos\ 29^{\circ}=Adjacent\\ \therefore\ Adjacent=174.92kmCosθ=HypotenuseAdjecent⟹Cos 29∘ =200Adjacent⟹200 Cos 29∘=Adjacent∴ Adjacent=174.92km
Below is an image to show the triangle.
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