Prove that (sinx+cosx)^4 = sin^2 2x+ 2sin2x+1 where 90<x<180 . Hence, find the value of x if (sinx + cosx)^4=0
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Expert's answer
2021-09-29T17:22:18-0400
We have to use the trigonometric equivalences for the sum of angles and the pitagoric relation to find:
(sinx+cosx)4=((sinx+cosx)2)2=(sin2x+cos2x+2sinxcosx)2Then we use the relationssin2x+cos2x=1and 2sinxcosx=sin2xto find(sinx+cosx)4=(1+sin2x)2(sinx+cosx)4=1+2sin2x+sin22x
Then, after we prove that (sinx+cosx)4=1+2sin2x+sin22x, we use one of the relation to find the value of x that safisfies (sinx+cosx)4=0
Now, since we need a value for x that implies a positive value for the sine and a negative value for the cosine under 90<x<180 and that also has to be equal in magnitude, which implies that x has to be 135° since
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