Question 23160
1. g(x)=5x2−25g(x) = \frac{5}{x^2 - 25}g(x)=x2−255 , domain includes all real numbers, except those, which turn the denominator to zero. Hence, D(g(x))=R∖(5;−5)D(g(x)) = R \setminus (5; -5)D(g(x))=R∖(5;−5) .
2. f(t)=3t2+5t+2f(t) = 3t^{2} + 5t + 2f(t)=3t2+5t+2 . Obviously, x∈Rx \in Rx∈R .
3. h(x)=5x−2h(x) = \sqrt{5x - 2}h(x)=5x−2 . Square root is defined to non-negative real numbers, so D(h(x)):x∈[25;∞)D(h(x)): x \in [\frac{2}{5}; \infty)D(h(x)):x∈[52;∞) .
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