Solve, write your answer in interval notation and graph the solution set.
14c. ∣2x−1∣+7 greater than or equal to 1
14d. ∣5x+3∣ less than or equal to -1
Solution:
14c. ∣2x−1∣+7≥1
∣2x−1∣≥−6
It is known, that ∣a∣≥0, so, obviously, ∣2x−1∣≥0⇒∣2x−1∣≥−6 ∀x
Answer: (−∞;+∞)
14d. ∣5x+3∣≤−1
It is known, that ∣a∣≥0, so it can't be ≤0, or ≤−1. Obviously, our equation has no solution.
Answer: empty set (no solutions).