Question #22677

Solve, write your answer in interval notation and graph the solution set.

14c. |2x-1|+7 greater than or equal to 1

14d. |5x+3| less than or equal to -1

Expert's answer

Solve, write your answer in interval notation and graph the solution set.

14c. 2x1+7|2x - 1| + 7 greater than or equal to 1

14d. 5x+3|5x + 3| less than or equal to -1

Solution:

14c. 2x1+71|2x - 1| + 7 \geq 1

2x16|2x - 1| \geq -6


It is known, that a0|a| \geq 0, so, obviously, 2x102x16 x|2x - 1| \geq 0 \Rightarrow |2x - 1| \geq -6 \ \forall x

Answer: (;+)(-\infty; +\infty)

14d. 5x+31|5x + 3| \leq -1

It is known, that a0|a| \geq 0, so it can't be 0\leq 0, or 1\leq -1. Obviously, our equation has no solution.

Answer: empty set (no solutions).

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