Question #22414

Solve, write your answer in interval notation and graph the solution set.

14a. |5y-2| less than 13

14b. |x+1| greater than or equal to 5

Expert's answer

Solve, write your answer in interval notation and graph the solution set.

14a. 5y2<13|5y - 2| < 13

14b. x+15|x + 1| \geq 5

**Solution:**

14a 5y2<13|5y - 2| < 13

13<5y2<1313+2<5y<13+211<5y<15115<y<3y(0.22,3)\begin{array}{l} -13 < 5y - 2 < 13 \\ -13 + 2 < 5y < 13 + 2 \\ -11 < 5y < 15 \\ -\frac{11}{5} < y < 3 \\ y \in (-0.22, 3) \\ \end{array}0.22+03y\xrightarrow[ -0.22]{+} \begin{array}{c} \text{0} \\ 3 \end{array} \xrightarrow{\text{y}}


**Answer:** y(0.22,3)y \in (-0.22, 3)

14b. x+15|x + 1| \geq 5

[x+15x+15[x4x6x(,6][4,+)\begin{array}{l} \left[ \begin{array}{l} x + 1 \geq 5 \\ x + 1 \leq -5 \end{array} \right. \\ \left[ \begin{array}{l} x \geq 4 \\ x \leq -6 \end{array} \right. \\ x \in (-\infty, -6] \cup [4, +\infty) \\ \end{array}6+04y\xrightarrow[ -6]{+} \begin{array}{c} \text{0} \\ 4 \end{array} \xrightarrow{\text{y}}


**Answer:** x(,6][4,+)x \in (-\infty, -6] \cup [4, +\infty)

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