Question

Solve, write your answer in interval notation and graph the solution set.

13a. 9 - 2x greater than or equal to 5

13b. (x/2) greater than (2x-3)/5 + 1

Answer 1

Solve, write your answer in interval notation and graph the solution set.

13a. $9 - 2x \geq 5$

13b. $\frac{x}{2} > \frac{2x - 3}{5} + 1$

**Solution:**

13a. $9 - 2x \geq 5$

$$\begin{array}{l} - 2x \geq -4 \\ x \leq 2 \\ x \in (-\infty, 2] \\ \end{array}$$

**Answer:** $x \in (-\infty, 2]$

13b. $\frac{x}{2} > \frac{2x - 3}{5} + 1$

$$\begin{array}{l} \frac{x}{2} - \frac{2x - 3}{5} > 1 \\ \frac{5x - 4x + 6}{10} > 1 \\ x + 6 > 10 \\ x > 4 \\ x \in (4, +\infty) \\ \end{array}$$

**Answer:** $x \in (4, +\infty)$