tan x =1/2 and the terminal side of the angle is in the II quadrant ,then cos x =?
"tanx =\\frac{1}{2} \\implies x=tan^{-1}0.5\\\\=26.57^0\\\\\\text{Since the terminal side of the angle is in the 2nd quadrant, we have that $x=180^0-26.57^0$}\\\\\\implies x=153.43^0\n\\\\\\text{Hence $cosx=-0.8944$}"
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