tan x =1/2 and the terminal side of the angle is in the II quadrant ,then cos x =?
tanx=12 ⟹ x=tan−10.5=26.570Since the terminal side of the angle is in the 2nd quadrant, we have that x=1800−26.570 ⟹ x=153.430Hence cosx=−0.8944tanx =\frac{1}{2} \implies x=tan^{-1}0.5\\=26.57^0\\\text{Since the terminal side of the angle is in the 2nd quadrant, we have that $x=180^0-26.57^0$}\\\implies x=153.43^0 \\\text{Hence $cosx=-0.8944$}tanx=21⟹x=tan−10.5=26.570Since the terminal side of the angle is in the 2nd quadrant, we have that x=1800−26.570⟹x=153.430Hence cosx=−0.8944
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