Question #22328

Solve the given equation by factoring.

5a. x^2+2x+5=0

5b. 6x^2+7x+2=0

Expert's answer

1. x2+2x+5=0x^{2} + 2x + 5 = 0

x2+2x+11+5=0x ^ {2} + 2 x + 1 - 1 + 5 = 0(x+1)2=4(x + 1) ^ {2} = - 4x+1=±4x + 1 = \pm \sqrt {- 4}x+1=±2ix + 1 = \pm 2 ix1=2i1x _ {1} = 2 i - 1x2=2i1x _ {2} = - 2 i - 1


2. 6x2+7x+2=06x^{2} + 7x + 2 = 0

ac=12a c = 1 26x2+3x+4x+2=06 x ^ {2} + 3 x + 4 x + 2 = 03x(2x+1)+2(2x+1)=03 x (2 x + 1) + 2 (2 x + 1) = 0(3x+2)(2x+1)=0(3 x + 2) (2 x + 1) = 0x1=23x2=12x _ {1} = - \frac {2}{3} \quad x _ {2} = - \frac {1}{2}

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