Question

Find the Discriminant

10. x^2-12x+36=0

11. 5x^2=x

12. 2x^2= -x-12

Answer 1

Find the Discriminant

10. $x^2 - 12x + 36 = 0$

11. $5x^2 = x$

12. $2x^2 = -x - 12$

$D$ - discriminant

$D = b^{2} - 4ac$

10. $x^{2} - 12x + 36 = 0$

$D = 12^{2} - 4 \cdot 1 \cdot 36 = 0$

11. $5x^{2} = x$

$5x^{2} - x = 0$

$D = (-1)^{2} - 4 \cdot 5 \cdot 0 = 1$

12. $2x^{2} = -x - 12$

$2x^{2} + x + 12 = 0$

$D = 1^{2} - 4 \cdot 2 \cdot 12 = -95$