Question #22116

Solve by using the Square Root Method

3. 3x^2=75

4. (5x+3)^2=12

Expert's answer

Solve by using the Square Root Method

3. 3x2=753x^2 = 75

4. (5x+3)2=12(5x + 3)^2 = 12

Solution

3.


3x2=75,3x^2 = 75,x2=753=25,x^2 = \frac{75}{3} = 25,x=±25=±5.x = \pm \sqrt{25} = \pm 5.


Answer: x1=5x_1 = 5, x2=5x_2 = -5.

4.


(5x+3)2=12,(5x + 3)^2 = 12,5x+3=±12=±23;5x + 3 = \pm \sqrt{12} = \pm 2\sqrt{3};


a) 5x+3=23,x=23355x + 3 = 2\sqrt{3}, x = \frac{2\sqrt{3} - 3}{5};

b) 5x+3=23,x=23355x + 3 = -2\sqrt{3}, x = \frac{-2\sqrt{3} - 3}{5}.

Answer: x1=2335,x2=2335x_1 = \frac{2\sqrt{3} - 3}{5}, x_2 = \frac{-2\sqrt{3} - 3}{5}.

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