1c. $(3x + 2) / 5 < = x - 1$ we have $3x + 2 < = 5^{*}(x - 1)$ $3x + 2 < = 5x - 5$ $2 + 5 < = 5x - 3x$ $7 < = 2x$ $3.5 < = x$
2a. ∣2y+5∣>1|2y + 5| > 1∣2y+5∣>1
so 2y+5>12y + 5 > 12y+5>1 or 2y+5<−12y + 5 < - 12y+5<−1
so 2y>−42y > -42y>−4 or 2y<−62y < -62y<−6
we get y>−2y > -2y>−2 or y<−3y < - 3y<−3
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