If f(x)=x2+3 and g(x)=3x−1 then find the following
1a. (f+g)(x)
1b. (f+g)(3)
1c. (f−g)(x)
**Solution:**
1a. (f+g)(x)=f(x)+g(x)=x2+3+3x−1=x2+3x+2
Answer: x2+x+2
1b. (f+g)(3)=(x2+3x+2)∣x=3=9+9+2=20
Answer: 20
1c. (f−g)(x)=f(x)−g(x)=x2+3−(3x−1)=x2−3x+4
Answer: x2−3x+4