Question

solve each quadratic in form equation

3. (x-5)^2+2(x-5)-35=0

Answer 1

$$(x - 5)^2 + 2(x - 5) - 35 = 02$$ $$x - 5 = t$$ $$t^2 + 2t - 35 = 0$$ $$D = 4 + 4 \cdot 35 = 144 = 12^2$$ $$t_{1,2} = \frac{-2 \pm 12}{2}$$ $$t_1 = -7 \quad t_2 = 5$$ $$x - 5 = -7 \quad \text{or} \quad x - 5 = 5$$ $$x = -2 \quad \text{or} \quad x = 10$$