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Answer to Question #20251 in Trigonometry for Kristen Woods
Question #20251
solve each quadratic in form equation
1. 4y^4+9=13y^2
1. 4y^4+9=13y^2
Expert's answer
let t=y^2 then
4t^2-13t+9=0
D=13^2-4*9*4=169-144=25
t12=(13+-5)/8 so t1=1, t2=9/4
but t=y^2
so y^2=1 or y^2=9/4
y1=1, y2=-1, y3=-3/2, y4=3/2
4t^2-13t+9=0
D=13^2-4*9*4=169-144=25
t12=(13+-5)/8 so t1=1, t2=9/4
but t=y^2
so y^2=1 or y^2=9/4
y1=1, y2=-1, y3=-3/2, y4=3/2
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