Write the standard form of the equation of the circle with the given conditions.
1a. Center (9,−10)(9, -10)(9,−10) and r=5r = 5r=5
1b. Center (2,0)(2,0)(2,0) and r=2r = \sqrt{2}r=2
**Solution:**
The standard form of the equation of the circle is (x−x0)2+(y−y0)2=r2(x - x_0)^2 + (y - y_0)^2 = r^2(x−x0)2+(y−y0)2=r2
Where C(x0,y0)C(x_0, y_0)C(x0,y0)
So we have
1a. (x−9)2+(y+10)2=25(x - 9)^2 + (y + 10)^2 = 25(x−9)2+(y+10)2=25
1b. (x−2)2+y2=2(x - 2)^2 + y^2 = 2(x−2)2+y2=2
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