Determine the measures of and to the nearest tenth of a degree, and the length of side
AB to one decimal place.
A B
C
3
4
D
A= C=
Side
AB=
Figure:
here,
cos62°=l(AB)12 ⇒l(AB)=12×cos62°⇒AB=12×0.469=5.63 cm\cos62\degree=\dfrac{l(AB)}{12}\\\ \\\Rightarrow l(AB)=12\times \cos62\degree\\\Rightarrow AB=12\times 0.469 =5.63\ cmcos62°=12l(AB) ⇒l(AB)=12×cos62°⇒AB=12×0.469=5.63 cm
Hence, AB=6.6 cm\boxed{AB=6.6\ cm}AB=6.6 cm
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