Answer to Question #194264 in Trigonometry for Bill

Question #194264

If sin (B) = -1/3 with B with B in Quadrant 3, find tan (B/2).

Expert's answer

If sin (B) = -1/3 and it is in 3 Quadrant where sinus turns negative. Then B = arcsin(-1/3)= arcsin(- 0.3333)= - 0.3398. Then tan(B/2)=tan(- 0.3398/2) =tan(- 0.1699) =- 0.002965 ≈ - 0.003.

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