Question

Perform the indicated operation.

3y^2+12/3y^2-15y divided by y^4-16/y^2-3y-10

the values that would be excluded from the domain are?

Answer 1

Conditions

Perform the indicated operation.

$3y^2 + 12/3y^2 - 15y$ divided by $y^4 - 16/y^2 - 3y - 10$

the values that would be excluded from the domain are?

Solution

$$\frac{\frac{3y^2 + 12}{3y^2 - 15y}}{\frac{y^4 - 16}{y^2 - 3y - 10}} = \frac{3y^2 + 12}{3y^2 - 15y} \cdot \frac{y^2 - 3y - 10}{y^4 - 16}$$

The excluded values will be all those values, for which each denominator in this fraction could be equal to 0.

In another words, we must find those $y$, when:

$$3y^2 - 15y = 0, y = 0, y = 5$$ $$y^4 - 16 = 0, y = 2, y = -2$$

Answer: The excluded values for $y$ are 0, 5, 2 and -2