Question #186437

(sinx+cosx)2 -sin(2x)=1


1
Expert's answer
2021-05-07T14:31:18-0400

(sinx+cosx)2sin2x=1sin2x+cos2x+2sinxcosxsin2x=1sin2x+cos2x+2sinxcosx(2sinxcosx)=11+2sinxcosx(2sinxcosx)=11=1(\sin{x}+\cos{x})^2-\sin{2x}=1\\ \sin^2{x}+\cos^2{x}+2\sin{x}*\cos{x}-\sin{2x}=1\\ \sin^2{x}+\cos^2{x}+2\sin{x}*\cos{x}-(2\sin{x}*\cos{x})=1\\ 1+2\sin{x}*\cos{x}-(2\sin{x}*\cos{x})=1\\ 1=1

Answer:x(;)x \in (-\infty;\infty)


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