Question #185419

If cosx+2cos(x+240°)=1

Determine the general equations


1
Expert's answer
2021-05-07T09:15:38-0400


Cos(x) + cos (x+240o) =1

    \implies

cos(x)+cos(x+24π18)=1cos(x)+cos(x+{24\pi \over18}) = 1


cos(x)+cos(x+24π18)=cos(0)cos(x)+cos(x+{24\pi \over18}) = cos(0)



We know that cos(a+b)=cos(a)cos(b)sin(a)sin(b)\boxed{cos(a+b) = cos(a)cos(b)-sin(a)sin(b)}

    \implies

cos(x)+cos(x)cos(24π/18)sin(x)sin(24π/18)=cos(0)\boxed{cos(x)+cos(x)cos(24\pi/18)-sin(x)sin(24\pi/18)=cos(0)}

On solving this

We got

x=13(6πn+π)\boxed{x = \frac{1}{3}(6\pi n +\pi)}




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