Question #177367

Evaluate: Lim x ²cos3x ÷ x³ + 4x²

x tend to 0


1
Expert's answer
2021-04-14T14:36:08-0400

limx2cos3xx3+4x2 as x tends to 0\text{lim}\frac{x^2cos3x}{x^3}+4x^2 \text{ as x tends to 0}

=limcos3xx+4x2=\text{lim}\frac{cos3x}{x}+4x^2

=limcos3xx+lim4x2=\text{lim}\frac{cos3x}{x}+lim4x^2

Using l’hopital rule we find limit for limcos3xx\text{Using l'hopital rule we find limit for } \text{lim}\frac{cos3x}{x}

=lim(3sinx) as x tends to 0 =lim(-3sinx)\text{ as x tends to 0 }

=0=0

lim4x2=0lim4x^2=0 as x tends to 0

Hence limx2cos3xx3+4x2=0Hence \text{ lim}\frac{x^2cos3x}{x^3}+4x^2 =0


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