Evaluate: Lim x ²cos3x ÷ x³ + 4x²
x tend to 0
limx2cos3xx3+4x2 as x tends to 0\text{lim}\frac{x^2cos3x}{x^3}+4x^2 \text{ as x tends to 0}limx3x2cos3x+4x2 as x tends to 0
=limcos3xx+4x2=\text{lim}\frac{cos3x}{x}+4x^2=limxcos3x+4x2
=limcos3xx+lim4x2=\text{lim}\frac{cos3x}{x}+lim4x^2=limxcos3x+lim4x2
Using l’hopital rule we find limit for limcos3xx\text{Using l'hopital rule we find limit for } \text{lim}\frac{cos3x}{x}Using l’hopital rule we find limit for limxcos3x
=lim(−3sinx) as x tends to 0 =lim(-3sinx)\text{ as x tends to 0 }=lim(−3sinx) as x tends to 0
=0=0=0
lim4x2=0lim4x^2=0lim4x2=0 as x tends to 0
Hence limx2cos3xx3+4x2=0Hence \text{ lim}\frac{x^2cos3x}{x^3}+4x^2 =0Hence limx3x2cos3x+4x2=0
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