Question #175856

1. An alternating current is given by the formula

I = 30 sin (50 t + 0.26) amps

a) Find the amplitude, periodic time, frequency, and phase angle

b) Find the value of the current at 18ms

c) Find the time at which the current first reaches 20 amps 

d) Plot the curve between 0 and 20ms


1
Expert's answer
2021-04-07T13:49:33-0400

Amplitude = 30

frequency

    50=ω=2Πf50=\omega=2\Pi f

f=50/2Π=7.957747155Hzf=50/2\Pi=7.957747155 Hz

periodic time

T=1/f=1/7.957747155=0.125663706secondsT=1/f=1/7.957747155=0.125663706 seconds

=125.663706ms=125.663706ms

phase angle

=0.26radians=0.26radians

=0.26180/π)=14.8969degrees=0.26*180^{\circ} /\pi)=14.8969 \, degrees


at 18 ms I=30sin(50(0.018)+0.26)=27.504I=30sin(50(0.018)+0.26)=27.504


20=30sin(50t+0.26)20=30sin(50t +0.26)

2/3=sin(50t+0.26)2/3=sin (50t+0.26)

41.8103149=50t+0.2641.8103149=50t+0.26

t=0.831006297secondst=0.831006297 seconds


graph


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Comments

Assignment Expert
07.04.21, 20:51

Dear VPM, we have already changed that formula, please read a solution of the question.

VPM
01.04.21, 11:05

Second mistake at 18 ms I=30sin(50(0.18)+0.26)=4.827I=30sin(50(0.18)+0.26)=4.827 i wanted to know if this equation is right because when I write it in my calculator it comes with a different number

Assignment Expert
30.03.21, 18:38

Dear Vm, thank you for correcting us.

Vm
30.03.21, 11:15

Second mistake at 18 ms I=30sin(50(0.18)+0.26)=4.827I=30sin(50(0.18)+0.26)=4.827 i dont get this when i do the working out

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