Question #175856

1. An alternating current is given by the formula

I = 30 sin (50 t + 0.26) amps

a) Find the amplitude, periodic time, frequency, and phase angle

b) Find the value of the current at 18ms

c) Find the time at which the current first reaches 20 amps 

d) Plot the curve between 0 and 20ms


Expert's answer

Amplitude = 30

frequency

    50=ω=2Πf50=\omega=2\Pi f

f=50/2Π=7.957747155Hzf=50/2\Pi=7.957747155 Hz

periodic time

T=1/f=1/7.957747155=0.125663706secondsT=1/f=1/7.957747155=0.125663706 seconds

=125.663706ms=125.663706ms

phase angle

=0.26radians=0.26radians

=0.26180/π)=14.8969degrees=0.26*180^{\circ} /\pi)=14.8969 \, degrees


at 18 ms I=30sin(50(0.018)+0.26)=27.504I=30sin(50(0.018)+0.26)=27.504


20=30sin(50t+0.26)20=30sin(50t +0.26)

2/3=sin(50t+0.26)2/3=sin (50t+0.26)

41.8103149=50t+0.2641.8103149=50t+0.26

t=0.831006297secondst=0.831006297 seconds


graph


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