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Answer to Question #17508 in Trigonometry for Vladimir Bautista
Question #17508
Find an algebraic expression for sin[arccos(3x)]. PLEASE show the steps
Expert's answer
sin( t )=sqrt(1-cos^2 ( t ) )
sin(arccos(3x))=sqrt(1-cos^2 (arccos(3x)))=sqrt(1-(3x)^2)=sqrt(1-9x^2)
sin(arccos(3x))=sqrt(1-cos^2 (arccos(3x)))=sqrt(1-(3x)^2)=sqrt(1-9x^2)
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