cos(π/3 + A) = sin(π/6 - A)
cos(π3+A)=cosπ3cosA−sinπ3sinA=sinπ6cosA−cosπ6sinA=sin(π6−A)\cos(\frac{\pi}{3} + A) = \cos\frac{\pi}{3} \cos A - \sin \frac{\pi}{3} \sin A = \sin\frac{\pi}{6} \cos A - \cos \frac{\pi}{6} \sin A = \sin (\frac{\pi}{6} - A)cos(3π+A)=cos3πcosA−sin3πsinA=sin6πcosA−cos6πsinA=sin(6π−A) as desired.
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