Question #168822

cos(π/3 + A) = sin(π/6 - A)


Expert's answer

cos(π3+A)=cosπ3cosAsinπ3sinA=sinπ6cosAcosπ6sinA=sin(π6A)\cos(\frac{\pi}{3} + A) = \cos\frac{\pi}{3} \cos A - \sin \frac{\pi}{3} \sin A = \sin\frac{\pi}{6} \cos A - \cos \frac{\pi}{6} \sin A = \sin (\frac{\pi}{6} - A) as desired.


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