Answer to Question #165305 in Trigonometry for Uma naik

Question #165305

Resolve that cos3A-cos5A by sin3A+sin5A = tanA

Expert's answer

"\\frac{2sin(\\frac{5A\u22123A}{2})cos(\\frac{5A+3A}{2})}{2cos(\\frac{5A+3A}{2})cos(\\frac{5A\u22123A}{2})}"

"\\frac{sinA}{cosA}"

"tanA"

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