Solution
sinu+sinq2sin(2u+q).cos(2u−q)sin(u+q)sin(u+q)(2)=(3)2sin(2u+q).cos(2u+q)tan(2u+q)cos(2u+q)sin(2u+q)Substituting(5)in(4),2sin(2u+q).37.sin(2u+q)sin2(2u+q)sin(2u+q)Accordingto(1),Whensin(2u+q)=+0.474Whensin(2u+q)=−0.474=6527=6527........................(1)=2sin(2u+q).cos(2u+q).........................(2)=1−tan2(2u+q)2tan(2u+q)=1−4992×73=2021.................................(3)=2021...............................(4)=73=73⟹cos(2u+q)=37sin(2u+q)............(5)=2021=409=±2103=+0.474or−0.474⟹cos(2u−q)=+0.438⟹cos(2u−q)=−0.438
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