Answer to Question #15431 in Trigonometry for mayra
simplify completely the trigonometric expressiong show all work neatly and in order
Tanx sinx secx
1
2012-09-25T10:50:57-0400
tanx=sinx/cosx
secx=1/cosx
Therefore
Tanx sinx secx=sinx/cosx * sinx *1/cosx=sin2x/cos2x=tan2x
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