Question #14905

If tan x = .76 and cos x = .22, what is sin x?



If sin x = .42, what is cos x?

Expert's answer

Conditions

1) If tanx=.76\tan x = .76 and cosx=.22\cos x = .22, what is sinx\sin x?

2) If sinx=.42\sin x = .42, what is cosx\cos x?

Solution

1)

This is a trigonometric task. Here we must use the Basic Trigonometric Identity. Its formula is:


sin2(x)+cos2(x)=1,xR.\sin^2(x) + \cos^2(x) = 1, \, x \in \mathbb{R}.


As it known, tan(x)=sin(x)cos(x)\tan(x) = \frac{\sin(x)}{\cos(x)}, so


sin(x)cos(x)=0.76sin(x)=0.76cos(x).cos(x)=0.22sin(x)=0.76×0.22=0.1672\frac{\sin(x)}{\cos(x)} = 0.76 \Rightarrow \sin(x) = 0.76 \cos(x). \quad \cos(x) = 0.22 \Rightarrow \sin(x) = 0.76 \times 0.22 = 0.1672


2)

This task is logically near previous. We use the same formula:


sin2(x)+cos2(x)=1,xR.\sin^2(x) + \cos^2(x) = 1, \, x \in \mathbb{R}.sin2(x)+cos2(x)=(0.42)2+cos2(x)=1cos2(x)=10.1764=0.8236cos(x)=±0.8236\begin{array}{l} \sin^2(x) + \cos^2(x) = (0.42)^2 + \cos^2(x) = 1 \Rightarrow \cos^2(x) = 1 - 0.1764 = 0.8236 \\ \Rightarrow \cos(x) = \pm \sqrt{0.8236} \\ \end{array}


This value is irrational, so we can leave it in this form.

Answer:

1) sin(x)=0.1672\sin(x) = 0.1672

2) Two solutions: cos(x)=0.8236\cos(x) = \sqrt{0.8236} or cos(x)=0.8236\cos(x) = -\sqrt{0.8236}

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