Let us complete the Pythagorean Identity:
"\\csc^2(x)\u2212\\cot^2(x)=(\\frac{1}{\\sin x})^2-(\\frac{\\cos x}{\\sin x})^2=\\frac{1}{\\sin^2 x}-\\frac{\\cos^2 x}{\\sin^2 x}=\\frac{1-\\cos^2 x}{\\sin^2 x}=\\frac{\\sin^2 x}{\\sin^2 x}=1."
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