tan(x)csc(x)cos(x)=1tan(x)csc(x)cos(x)=1tan(x)csc(x)cos(x)=1
But
tan(x)=sin(x)cos(x)tan(x)=\frac{sin(x)}{cos(x)}tan(x)=cos(x)sin(x) and csc(x)=1sin(x)csc(x)=\frac{1}{sin(x)}csc(x)=sin(x)1
Simplifying L.H.S
sin(x)cos(x)×1sin(x)×cos(x)\frac{sin(x)}{cos(x)}\times\frac{1}{sin(x)}\times cos(x)cos(x)sin(x)×sin(x)1×cos(x)
=1=1=1
Since L.H.S=1 and R.H.S =1. Hence verified.
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