a) sin(π\piπ )cos(π\piπ/6) + cos(π\piπ )sin(π\piπ/6) = 0 + (-1)(1/2) = -1/2
b) tan(π\piπ/4 + π\piπ) = (tan(π\piπ /4) + tan(π\piπ)) / (1-tan(π\piπ/4)tan(π\piπ)) = (1 + 0)/(1-0) = 1
c) cos (-)(π\piπ +π\piπ/4) = cos(π\piπ+ π\piπ /4) = cos(π\piπ )cos(π\piπ/4) - sin(π\piπ)sin(π\piπ/4) = (-1)(1/ 2\sqrt{2}2 ) + 0 = -1/2\sqrt{2}2
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment