Answer to Question #138417 in Trigonometry for Joseph Osei Amoako

Question

given that tan y=√2, where x and y are acute angles. find cos y?

Answer 1

tan y = $\sqrt{2}$ Is also the same as,

tan y = $\frac{\sqrt{2}}{1}$

Hence

$\sqrt{2}$ Is the opposite while $1$ is the adjacent.

Hence

Hypotenuse(H) = $\sqrt{(\sqrt{2})^2+1^2}$

H = $\sqrt{3}$

Therefore cos y = $\frac{Adjacent}{Hypotenuse}$

Cos y = $\frac{1}{\sqrt{3}}$