Question #13653

cos(pi/8)*cos(7pi/8)*cos(3pi/8)*cos(5pi/8)
1

Expert's answer

2012-08-30T09:06:02-0400
cosπ8cos7π8cos3π8cos5π8=cosπ8cos(ππ8)cos3π8cos(π3π8)=cosπ8(cosπ8)cos3π8(cos3π8)=cos2π8cos23π8=(cosπ8cos3π8)2=(12[cos(π8+3π8)+cos(3π8π8)])2=14(cos(π2)+cos(π4))2=1412=18\begin{array}{l} \cos \frac {\pi}{8} * \cos \frac {7 \pi}{8} * \cos \frac {3 \pi}{8} * \cos \frac {5 \pi}{8} = \cos \frac {\pi}{8} * \cos \left(\pi - \frac {\pi}{8}\right) * \cos \frac {3 \pi}{8} * \cos \left(\pi - \frac {3 \pi}{8}\right) \\ = \cos \frac {\pi}{8} * (- \cos \frac {\pi}{8}) * \cos \frac {3 \pi}{8} * (- \cos \frac {3 \pi}{8}) = \cos^ {2} \frac {\pi}{8} * \cos^ {2} \frac {3 \pi}{8} \\ = \left(\cos \frac {\pi}{8} * \cos \frac {3 \pi}{8}\right) ^ {2} = \left(\frac {1}{2} \left[ \cos \left(\frac {\pi}{8} + \frac {3 \pi}{8}\right) + \cos \left(\frac {3 \pi}{8} - \frac {\pi}{8}\right) \right]\right) ^ {2} \\ = \frac {1}{4} \left(\cos \left(\frac {\pi}{2}\right) + \cos \left(\frac {\pi}{4}\right)\right) ^ {2} = \frac {1}{4} * \frac {1}{2} = \frac {1}{8} \\ \end{array}

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS