Question #13643

1/sinA+cosA+1/sinA-cosA
1

Expert's answer

2012-08-30T09:07:20-0400
1sinα+cosα+1sinαcosα=sinαcosα+sinα+cosα(sinα+cosα)(sinαcosα)=2sinαsin2αcos2α=2sinαsin2α(1sin2α)=2sinα2sin2α1\frac {1}{\sin \alpha + \cos \alpha} + \frac {1}{\sin \alpha - \cos \alpha} = \frac {\sin \alpha - \cos \alpha + \sin \alpha + \cos \alpha}{(\sin \alpha + \cos \alpha) (\sin \alpha - \cos \alpha)} = \frac {2 \sin \alpha}{\sin^ {2} \alpha - \cos^ {2} \alpha} = \frac {2 \sin \alpha}{\sin^ {2} \alpha - (1 - \sin^ {2} \alpha)} = \frac {2 \sin \alpha}{2 \sin^ {2} \alpha - 1}

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