Question #133178
prove that
2sin^2theta+2cos^2theta-1=0
1
Expert's answer
2020-09-20T18:06:24-0400

2sin2θ+2cos2θ1=2(sin2θ+cos2θ)1=21=12\sin^2\theta + 2\cos^2\theta -1 = 2*(sin^2\theta + \cos^2\theta) - 1 = 2-1 =1

for any value θ\theta

hence the assumption 2sin2θ+2cos2θ1=02\sin^2\theta + 2\cos^2\theta -1 = 0 is not true


Answer: The original hypothesis requiring proof is false


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