4. Find the exact value of tan(sin-1(-1/2))
tan(sin−1(−1/2))=sin(sin−1(−1/2))/cos(sin−1(−1/2));tan(sin^{-1}(-1/2)) = sin(sin^{-1}(-1/2))/cos(sin^{-1}(-1/2));tan(sin−1(−1/2))=sin(sin−1(−1/2))/cos(sin−1(−1/2));
By the definition of inverse function( sin(sin−1(x))=x)sin(sin^{-1}(x)) = x)sin(sin−1(x))=x) :
tan(sin−1(−1/2))=−1/2∗cos(sin−1(−1/2));tan(sin^{−1} (−1/2)) = -1/2*cos(sin^{-1}(-1/2));tan(sin−1(−1/2))=−1/2∗cos(sin−1(−1/2));
By the Pythagorean identity:
cos(sin−1(−1/2))=1−sin2(sin−1(−1/2))=3/2cos(sin^{-1}(-1/2)) = \sqrt{1-sin^2(sin^{-1}(-1/2))} = \sqrt3/2cos(sin−1(−1/2))=1−sin2(sin−1(−1/2))=3/2;
tan(sin−1(−1/2))=−1/3=−3/3tan(sin^{-1}(-1/2)) = -1/\sqrt3 = -\sqrt3/3tan(sin−1(−1/2))=−1/3=−3/3
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