Question #132598

4. Find the exact value of tan(sin-1(-1/2))


1
Expert's answer
2020-09-13T18:13:43-0400

tan(sin1(1/2))=sin(sin1(1/2))/cos(sin1(1/2));tan(sin^{-1}(-1/2)) = sin(sin^{-1}(-1/2))/cos(sin^{-1}(-1/2));

By the definition of inverse function( sin(sin1(x))=x)sin(sin^{-1}(x)) = x) :

tan(sin1(1/2))=1/2cos(sin1(1/2));tan(sin^{−1} (−1/2)) = -1/2*cos(sin^{-1}(-1/2));

By the Pythagorean identity:

cos(sin1(1/2))=1sin2(sin1(1/2))=3/2cos(sin^{-1}(-1/2)) = \sqrt{1-sin^2(sin^{-1}(-1/2))} = \sqrt3/2;

tan(sin1(1/2))=1/3=3/3tan(sin^{-1}(-1/2)) = -1/\sqrt3 = -\sqrt3/3


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