Find the exact value of tan (sin-1(-1/2))
sin−1(−12)=−30osin^{-1}(-\frac{1}{2}) = -30^ osin−1(−21)=−30o Or 150o150^o150o
tan150o=−13tan 150 ^o= - \frac{1}{\sqrt3}tan150o=−31
tan(sin−1(−12))=tan(sin^{-1}(-\frac{1}{2})) =tan(sin−1(−21))= −13-\frac{1}{\sqrt3}−31
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