Question #129850

Find the exact value of tan (sin-1(-1/2))




1
Expert's answer
2020-08-23T17:05:41-0400

sin1(12)=30osin^{-1}(-\frac{1}{2}) = -30^ o Or 150o150^o


tan150o=13tan 150 ^o= - \frac{1}{\sqrt3}


tan(sin1(12))=tan(sin^{-1}(-\frac{1}{2})) = 13-\frac{1}{\sqrt3}



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