Answer to Question #128838 in Trigonometry for Ilya

Question

sin(x)=1/2; -pi/2<x<pi/2; find the x

Answer 1

sin(x) = 1/2

sin(x) = sin($\pi$/6)

x = $\pi$/6

$\pi$/6 { -$\pi$/2<x<$\pi$/2 }