Question #127319

sin 60 cos30 cos60 sin30 sin30 o o o o o

Expert's answer


Let X = sin⁡60°∗cos⁡30°∗cos⁡60°∗sin⁡30°∗sin⁡30°\sin 60\degree * \cos 30\degree * \cos 60\degree * \sin 30\degree * \sin 30\degree


sin⁡60°=3/2\sin 60\degree = \sqrt{3}/2

cos⁡30°=3/2\cos 30\degree = \sqrt{3}/2

cos⁡60°=1/2\cos 60\degree = 1/2

sin⁡30°=1/2\sin 30\degree = 1/2


So substituting the above values in X

∴\therefore X = 3/2\sqrt{3}/2 * 3/2\sqrt{3}/2 * 0.50.5 * 0.50.5 * 0.50.5


= 3/32




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