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Answer to Question #11462 in Trigonometry for safanussrath
Question #11462
prove that
a)cos(90-/theta)cosec(90-/theta)=tan/theta
a)cos(90-/theta)cosec(90-/theta)=tan/theta
Expert's answer
cos(90-/theta)cosec(90-/theta)=tan/theta
First of all, cos(90-/theta)=sin(/theta)
also cosec(90-/theta)=1/sin(90-/theta)=1/cos(/theta)
So we have& cos(90-/theta)cosec(90-/theta)= sin(/theta)/cos(/theta)=tan/theta
First of all, cos(90-/theta)=sin(/theta)
also cosec(90-/theta)=1/sin(90-/theta)=1/cos(/theta)
So we have& cos(90-/theta)cosec(90-/theta)= sin(/theta)/cos(/theta)=tan/theta
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