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G⃗=〖5t〗2i+tj−t3k and
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F⃗=sinti–costj, what is
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d/dt(G×F⃗)
G=−2i+tj−3tkG=-2i+tj-3tkG=−2i+tj−3tk
F=isint+jcostF=isint+jcostF=isint+jcost
G×F=∣ijk−2t−3tsintcost0∣=3ticost−3tjsint−(2cost+tsint)kG\times F=\begin{vmatrix} i & j&k \\ -2 & t&-3t \\ sint&cost&0 \\ \end{vmatrix}=3ticost-3tjsint-(2cost+tsint)kG×F=∣∣i−2sintjtcostk−3t0∣∣=3ticost−3tjsint−(2cost+tsint)k
ddt(G×F)=(3cost−3tsint)i−(3sint+3tcost)j−(sint+tcost−2sint)k=\frac{d}{dt}(G\times F)=(3cost-3tsint)i-(3sint+3tcost)j-(sint+tcost-2sint)k=dtd(G×F)=(3cost−3tsint)i−(3sint+3tcost)j−(sint+tcost−2sint)k=
=3(cost−tsint)i−3(sint+tcost)j−(tcost−sint)k=3(cost-tsint)i-3(sint+tcost)j-(tcost-sint)k=3(cost−tsint)i−3(sint+tcost)j−(tcost−sint)k
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